同步模式--wait/notify、lock、park/unpark
09 Feb 2020 -
3 minute read
运行顺序:必须先2后1
wait-notify版
// 用来同步的对象
static Object obj = new Object();
// t2 运行标记, 代表 t2 是否执行过
static boolean t2runed = false;
public static void main(String[] args) {
Thread t1 = new Thread(() -> {
synchronized (obj) {
// 如果 t2 没有执行过
while (!t2runed) {
try {
// t1 先等一会
obj.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
System.out.println(1);
});
Thread t2 = new Thread(() -> {
System.out.println(2);
synchronized (obj) {
// 修改运行标记
t2runed = true;
// 通知 obj 上等待的线程(可能有多个,因此需要用 notifyAll)
obj.notifyAll();
}
});
t1.start();
t2.start();
}
park/unpark 版本
可以看到,实现上很麻烦:
- 首先,需要保证先 wait 再 notify,否则 wait 线程永远得不到唤醒。因此使用了『运行标记』来判断该不该 wait
- 第二,如果有些干扰线程错误地 notify 了 wait 线程,条件不满足时还要重新等待,使用了 while 循环来解决 此问题
- 最后,唤醒对象上的 wait 线程需要使用 notifyAll,因为『同步对象』上的等待线程可能不止一个
可以使用 LockSupport 类的 park 和 unpark 来简化上面的题目:
Thread t1 = new Thread(() -> {
try { Thread.sleep(1000); } catch (InterruptedException e) { }
// 当没有『许可』时,当前线程暂停运行;有『许可』时,用掉这个『许可』,当前线程恢复运行
LockSupport.park();
System.out.println("1");
});
Thread t2 = new Thread(() -> {
System.out.println("2");
// 给线程 t1 发放『许可』(多次连续调用 unpark 只会发放一个『许可』)
LockSupport.unpark(t1);
});
t1.start();
t2.start();
park 和 unpark 方法比较灵活,他俩谁先调用,谁后调用无所谓。并且是以线程为单位进行『暂停』和『恢复』, 不需要『同步对象』和『运行标记』
交替输出
线程 1 输出 a 5 次,线程 2 输出 b 5 次,线程 3 输出 c 5 次。现在要求输出 abcabcabcabcabc 怎么实现
wait notify版
class SyncWaitNotify {
private int flag;
private int loopNumber;
public SyncWaitNotify(int flag, int loopNumber) {
this.flag = flag;
this.loopNumber = loopNumber;
}
public void print(int waitFlag, int nextFlag, String str) {
for (int i = 0; i < loopNumber; i++) {
synchronized (this) {
while (this.flag != waitFlag) {
try {
this.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.print(str);
flag = nextFlag;
this.notifyAll();
}
}
}
}
SyncWaitNotify syncWaitNotify = new SyncWaitNotify(1, 5);
new Thread(() -> {
syncWaitNotify.print(1, 2, "a");
}).start();
new Thread(() -> {
syncWaitNotify.print(2, 3, "b");
}).start();
new Thread(() -> {
syncWaitNotify.print(3, 1, "c");
}).start();
Lock版本
class AwaitSignal extends ReentrantLock {
public void start(Condition first) {
this.lock();
try {
log.debug("start");
first.signal();
} finally {
this.unlock();
}
}
public void print(String str, Condition current, Condition next) {
for (int i = 0; i < loopNumber; i++) {
this.lock();
try {
current.await();
log.debug(str);
next.signal();
} catch (InterruptedException e) {
e.printStackTrace();
} finally {
this.unlock();
}
}
}
// 循环次数
private int loopNumber;
public AwaitSignal(int loopNumber) {
this.loopNumber = loopNumber;
}
}
AwaitSignal as = new AwaitSignal(5);
Condition aWaitSet = as.newCondition();
Condition bWaitSet = as.newCondition();
Condition cWaitSet = as.newCondition();
new Thread(() -> {
as.print("a", aWaitSet, bWaitSet);
}).start();
new Thread(() -> {
as.print("b", bWaitSet, cWaitSet);
}).start();
new Thread(() -> {
as.print("c", cWaitSet, aWaitSet);
}).start();
as.start(aWaitSet);
该实现没有考虑 a,b,c 线程都就绪再开始
Park Unpark版本
class SyncPark {
private int loopNumber;
private Thread[] threads;
public SyncPark(int loopNumber) {
this.loopNumber = loopNumber;
}
public void setThreads(Thread... threads) {
this.threads = threads;
}
public void print(String str) {
for (int i = 0; i < loopNumber; i++) {
LockSupport.park();
System.out.print(str);
LockSupport.unpark(nextThread());
}
}
private Thread nextThread() {
Thread current = Thread.currentThread();
int index = 0;
for (int i = 0; i < threads.length; i++) {
if(threads[i] == current) {
index = i;
break;
}
}
if(index < threads.length - 1) {
return threads[index+1];
} else {
return threads[0];
}
}
public void start() {
for (Thread thread : threads) {
thread.start();
}
LockSupport.unpark(threads[0]);
}
}
SyncPark syncPark = new SyncPark(5);
Thread t1 = new Thread(() -> {
syncPark.print("a");
});
Thread t2 = new Thread(() -> {
syncPark.print("b");
});
Thread t3 = new Thread(() -> {
syncPark.print("c\n");
});
syncPark.setThreads(t1, t2, t3);
syncPark.start();